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Right here we are going to be taught multiplying 2-digit quantity by 1-digit
quantity. In two other ways we are going to be taught to multiply a two-digit quantity by a
one-digit quantity.
Examples of multiplying 2-digit quantity by 1-digit quantity with out Regrouping:
We could have a fast overview of multiplication of 2-digit quantity by 1-digit quantity with out regrouping:
1. Multiply 24 by 2.
|
T O 2 4 × 2 4 8 |
First multiply those by 2. 4 × 2 = 8. Write 8 underneath O. Now multiply the tens by 2. 3 × 3 = 9. Write 9 underneath T. |
2. Multiply 34 and a pair of
Resolution:
|
Step I: Prepare the numbers vertically. Step II: First multiply the digit on the ones place by 2. 2 × 4 = 8 ones Step III: Now multiply the digit on the tens place by 2. 2 × 3 = 6 tens |
 Thus, 34 × 2 = 68 |
3. Multiply 20 by 3 by utilizing expanded kind
Resolution:
20 → 2 tens + 0 ones
× 3 → × 3
6 tens + 0 ones
= 60 + 0
= 60
Due to this fact, 20 × 3 = 60
4. Multiply 50 by 1 by utilizing quick kind
Resolution:
50 → 50
× 1 → × 1
0 50
(i) First digit of 1’s place is multiplied by 1, i.e., 0 × 1 = 0
(ii) Then digit at ten’s place is multiplied by 1, i.e., 5 tens × 1 = 5 tens
Therefore, 50 × 1 = 50
Observe the next Instance utilizing Three Completely different Strategies:
5. Multiply 13 by 2.
Resolution:
First Methodology: Utilizing Repeated Addition.
13 x 2 = 13 + 13 = 26
Due to this fact, 13 x 2 = 26.
Second Methodology: Utilizing Expanded Kind
Contemplate 13 as 10 + 3.
13 × 2 = (10 + 3) × 2
= 10 × 2 + 3 × 2
= 20 + 6
= 26.
Third Methodology: Quick Kind
Write the numbers in response to place worth proven on the suitable.
Step I:
Multiply those:
3 ones × 2 = 6 ones
Write 6 underneath ones column.
Step II:
Multiply the tens:
1 ten × 2 = 2 tens
Write 2 underneath tens column.
Thus, the product of 13 and a pair of is 26.
Examples of multiplying 2-digit quantity by 1-digit quantity with Regrouping:
1. Multiply 66 by 3
|
T O 1 6 6 × 3 1 4 8 |
First multiply those by 3. 6 × 3 = 18 = one ten + 8 ones Write 8 underneath O. carry 1 ten Now multiply the tens by 3. 6 × 3 = 18 Add 1 to the product. 18 + 1 = 19 |
2. Multiply 25 by 3
|
Step I: Prepare the numbers vertically. Step II: First multiply the digit on the ones place by 3. 3 × 5 = 15 = 1 ten + 5 ones Write 5 within the ones column and carry over 1 to the tens Step III: Now multiply the digit on the tens place by 3. 3 × 2 = 6 tens Now, 6 + 1 (carry over) = 7 tens |
 Thus, 25 × 3 = 75 |
3. Multiply 46 by 4
|
Step I: Prepare the numbers vertically. Step II: Multiply the digit on the ones place by 4. 6 × 4 = 24 = 2 tens + 4 ones Write 4 within the ones column and carry over 2 to the tens Step III: Now multiply the digit on the tens place by 4. 4 × 4 = 16 tens Now, 16 + 2 (carry over) = 18 tens = 1 hundred + 8 tens Write 8 on the tens place and 1 on the hundred place. |
 Thus, |
4. Multiply 20 by 3 by utilizing expanded kind
Resolution:
20 → 2 tens + 0 ones
× 3 → × 3
6 tens + 0 ones
= 60 + 0
= 60
Due to this fact, 20 × 3 = 60
5. Multiply 26 by
7 by utilizing expanded kind
Resolution:
26 → 20 + 6 → 2 tens + 6 ones
× 7 → × 7 → × 7
(2 × 7) tens + (6 ×
7) ones
2 tens + 6 ones
× 7 ones
14 tens + 42 ones
= 14 tens + (40 + 2) ones
= 14 tens + 4 tens + 2 ones
= 18 tens + 2 ones
= 180 + 2
= 182
Due to this fact, 26 × 7 = 182
6. Multiply 48 by
6 by utilizing quick kind
Resolution:
48
× 6
24 ← 48
= 28 tens 8 ones
= 288
Therefore, 48 × 6 = 288
(i) 48 × 6 is written in column from.
(ii) 8 ones are multiplied by 6, i.e., 6 × 8 = 48 ones = 4
tens + 8 ones
8 is written is one’s column and 4 tens is gained.
(iii) Gained 4 is carried to the ten’s column.
(iv) Now 4 tens is multiplied by 6, i.e., 4 tens × 6 = 24
tens
(v) Carried 4 tens is added to 24 tens, i.e., 4 tens + 24
tens = 28 tens
7. Discover the
product of 58 × 5.
Resolution:
58
× 5
25 ← 40
= 25 + 4 ← 0
= 29 0
= 290
(i) 8 ones × 5 = 40 = 4 tens + 0 one
(ii) 5 tens × 5 = 25 tens
(iii) 25 tens + 4 tens = 29 tens
Therefore, 58 × 5 = 290
8. Multiply 37 by
8
Resolution:
3 7
× 8
5 6
+ 2 4 0
2 9 6
(i) 7 ones × 8 = 56 ones = 5 tens 6 ones
56 is positioned in such method that 5 comes underneath tens and 6 underneath
ones
(ii) 3 tens × 8 = 24 tens = 240 ones
= 2 a whole lot, 4 tens and 0 ones
240 is positioned under 56 in such method that 2 comes underneath a whole lot,
4 underneath tens and 0 underneath ones.
Therefore, 37 × 8 = 296
Questions and Solutions on Multiplying 2-Digit Quantity by 1-Digit Quantity:
Multiplication of 2-Digit Quantity by 1-Digit Quantity With out Regrouping:
I. Discover the product:
(i) 23 × 3 =
(ii) 44 × 2 =
(iii) 33 × 2 =
(iv) 22 × 4 =
(v) 32 × 3 =
(vi) 40 × 2 =
(vii) 43 × 2 =
(viii) 12 × 3 =
(ix) 23 × 2 =
(x) 11 × 9 =
(xi) 21 × 4 =
(xii) 13 × 3 =
Reply:
I. (i) 69
(ii) 88
(iii) 66
(iv) 44
(v) 96
(vi) 80
(vii) 86
(viii) 36
(ix) 46
(x) 99
(xi) 84
(xii) 39
Multiplication of 2-Digit Quantity by 1-Digit Quantity With Regrouping:
II. Discover the product:
(i) 46 × 2
(ii) 19 × 4
(iii) 27 × 3
(iv) 18 × 5
Reply:
II. (i) 92
(ii) 76
(iii) 81
(iv) 90
III. Multiply the next:
(i) 78 × 4
(ii) 63 × 6
(iii) 51 × 6
(iv) 39 × 8
(v) 72 × 9
(vi) 45 × 7
(vii) 17 × 4
(viii) 88 × 8
Reply:
III. (i) 312
(ii) 398
(iii) 306
(iv) 312
(v) 648
(vi) 315
(vii) 68
(viii) 704
IV. Remedy the next:
(i) 37 × 6
(ii) 72 × 4
(iii) 56 × 7
(iv) 84 × 2
(v) 45 × 9
Reply:
IV. (i) 37 × 6
(ii) 72 × 4
(iii) 56 × 7
(iv) 84 × 2
(v) 45 × 9
V. Multiply the next :
|
(i) T O 3 1 × 2 _______ |
(ii) T O 4 7 × 1 _______ |
|
(iii) T O 1 1 × 3 _______ |
(iv) T O 2 2 × 2 _______ |
|
(v) T O 2 3 × 2 _______ |
(vi) T O 2 6 × 3 _______ |
|
(vii) T O 4 9 × 2 _______ |
(viii) T O 2 3 × 4 _______ |
|
(ix) T O 1 6 × 6 _______ |
(x) T O 1 9 × 5 _______ |
|
(xi) T O 5 2 × 5 _______ |
(xii) T O 2 3 × 6 _______ |
|
(xiii) T O 6 4 × 9 _______ |
(xiv) T O 3 2 × 7 _______ |
|
(xv) T O 7 5 × 8 _______ |
VI. Multiply the next:
(i) 21 × 5 = _____
(ii) 34 × 2 = _____
(iii) 23 × 3 = _____
(iv) 27 × 3 = _____
(v) 38 × 2 = _____
(vi) 18 × 4 = _____
(vii) 25 × 8 = _____
(viii) 32 × 6 = _____
(ix) 29 × 4 = _____
(x) 45 × 5 = _____
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