Thursday, November 30, 2023
HomeMathAddition of Size | Study How the Values of Size are Organized

# Addition of Size | Study How the Values of Size are Organized

The method of addition of items of size is strictly much like addition of unusual numbers.

Learn the way the values of size are organized
in numerous columns for the addition of size.

1. Add 15 m 18 cm and 16 m 22 cm

Resolution:

Case 1:

Lengths to be added are transformed into cm.

15 m 18 cm = 1500 cm + 18 cm = 1518 cm

16 m 22 cm = 1600 cm + 22 cm = 1622 cm

Now, sum

1   1
1518 cm

+ 1622 cm
3140 cm

= 31 m 40 cm

Due to this fact, 15 m 18 cm + 16 m 22 cm = 31 m 40 cm

Case 2:

m     cm
1       1
15    18

+ 16    22
31    40

(i) First cm are added, 18 cm + 22 cm= 40 cm. This sum is positioned beneath cm column

(ii) Now meters are added, 15 m + 16 m = 31 m. This 31 m is positioned beneath m column.

Therefore, sum = 31 m 40 cm.

2. Add 16 m 17 cm and 20 m 23 cm

Resolution:

Case 1:

Lengths to be added are transformed into cm.

16 m 17 cm = 1600 cm + 17 cm = 1617 cm

20 m 23 cm = 2000 cm + 23 cm = 2023 cm

Now, sum

1
1617 cm

+ 2023 cm
3640 cm

= 36 m 40 cm

Due to this fact, 16 m 17 cm + 20 m 23 cm = 36 m 40 cm

Case 2:

m   cm
1
16   17
+ 20   23
36   40

(i) First cm are added, 17 cm + 23 cm= 40 cm. This sum is positioned beneath cm column

(ii) Now meters are added, 16 m + 20 m = 36 m. This 36 m is positioned beneath m column.

Therefore, sum = 36 m 40 cm.

3. Add 62 m 34 cm, 27 m 73 cm and 9 m 5 cm.

Resolution:

Thus, 62 m 34 cm + 27 m 73 cm + 9 m 5 cm = 99 m 12 cm

4. Add 45 m 37 cm and 31 m 92 cm.

Resolution:

Case 1:

45 m 37 cm = (45 × 100) cm + 37 cm = (4500
+ 37) cm = 4537 cm

31 m 92 cm = (31 × 100) cm + 92 cm = (3100
+ 92) cm = 3192 cm

Now, sum

1
4537 cm

+ 3192 cm
7729 cm

= 77 m 29 cm

Due to this fact, 45 m 37 cm + 31 m 92 cm = 77 m
29 cm

Case 2:

m   cm
1
45   37

+ 31   92
77   29

(i) 37 cm + 92 cm = 129 cm = 1 m 29 cm. 29
is positioned beneath cm column and 1 m is carried over to m column.

(ii) Now 1 m + 45 m + 31 m = 77 m. It’s
positioned beneath m column.

Therefore,
sum = 77 m 29 cm.

cm, 7 m 5 cm and 45 m 73 cm.

Resolution:

The values of size
are organized in columns of m and cm after which added.

m    cm
2 1   1
38   26

7   05

+  45   73

91   04

(i) 26 cm + 05 cm + 73 cm = 104 cm = 1 m 04 cm.

04 is positioned beneath cm column and 1 m is carried over.

(ii) 1 m + 38 m + 7 m + 45 m = 91 m and it’s positioned beneath m
column.

Therefore, the sum = 91 m
04 cm

6. Add 4 km 476 m
and 5 km 54 m.

Resolution:

Case 1:

Kilometers are turned into meters

4 km 476 m = (4 × 1000) m + 476 m = 4000 m + 476 m = 4476 m

5 km 54 m = (5 × 1000) m + 54 m = 5000 m + 54 m = 5054 m

Now sum                   1 1
4476 m

+  5054 m

9530 m

= 9 km 530 m

Due to this fact, 4 km 476 m +
5 km 54 m = 9 km 530 m

Case
2:

km    m
1 1
4   476

+ 5   054
9   530

(i) 476 m + 054 m = 530 m, which
goes beneath m.

(ii) 4 km + 5 km = 9 km, which
goes beneath km.

Therefore, the sum = 9 km
530 m

m, 28 km 54 m and eight km 181 m.

Resolution:

Kilometer and meter are organized in numerous columns and

km    m
2 1   1
37   963

28   054

+     8   181
74   198

(i) 963 m + 54 m + 181 m = 1198 m = 1 km 198 m.

198 m is positioned beneath column of meters and 1 km is carried
over.

(ii) 1 km + 37 km + 28 km + 8 km = 74 km

It’s positioned beneath km column.

Therefore, the sum = 74
km 198 m

following:

m   dm  cm

26
7     8

+  52   5     6

Resolution:

m   dm  cm
1       1
26    7    8

+  52    5    6
79    3    4

(i) 8 cm + 6 cm = 14 cm = 1 dm 4 cm

4 cm is positioned beneath cm column and 1 dm is carried over.

(ii) 7 dm + 5 dm + 1 dm = 13 dm = 1 m 3 dm

3 dm is positioned beneath dm column and 1 m is carried over.

(iii) 1 m + 26 m + 52 m = 79 m

Therefore, the sum = 79 m
3 dm 4cm

So as to add lengths, write the numbers of km, m and cm in separate columns then add like unusual numbers ranging from the best.

9. Add 46 km 143 m and 53 km 200 m.

km        m

46       143

+ 53       200

_  99       343

Due to this fact, 46 km 143 m and 53 km 200 m = 99 km 343 m

10. Add 28 km 76 m, 12 km 44 m & 21 km 38 m

km        m

28        76

12        44

+ 21        38

_ 62         58

Questions and Solutions on Addition of Size:

(i) 32 m 78 cm + 15 m + 9 cm

(ii) 22 m 98 cm + 63 m + 89 cm + 7 m 7 cm

(iii) 143 m 50 cm + 112 m + 76 cm + 84 m 45 cm

(iv) 78 m 36 cm + 15 m 8 cm

(v) 153 m 28 cm + 49 m 25 cm + 70 m 20 cm

(vi) 69 m 59 cm + 15 m 15 cm + 56 m 9 cm

Solutions

1. (i) 47 m 87 cm

(ii) 93 m 94 cm

(iii) 340 m 71 cm

(iv) 93 m 44 cm

(v) 272 m 73 cm

(vi) 140 m 83 cm

(i) 139 m 68 cm, 66 m 46 cm and 42 m 7 cm

(ii) 140 m 23 cm, 33 m 48 cm and 32 m 17 cm

(iii) 179 m 16 cm, 69 m 59 cm and seven m 6 cm

(iv) 35 m 50 cm, 317 m 46 cm and 93 m 47 cm

(v) 64 m 18 cm, 48 m 36 cm and 14 m 82 cm

Solutions

2. (i) 248 m 21 cm

(ii) 205 m 88 cm

(iii) 255 m 81 cm

(iv) 446 m 43 cm

(v) 127 m 36 cm

 (i) m         cm           18         00      +   23         00      ____________ (ii) m         cm           31         50      +   46         00      ____________
 (iii) m         cm           34         02      +   43         06      ____________ (iv) m         cm           68         25      +   36         70      ____________
 (v) m         cm           43         62      +   27         34      ____________ (vi) m         cm           93         75      +   29         25      ____________
 (vii) m         cm           74         50      +   58         70      ____________ (viii) m         cm           47         84      +    6         58      ____________

● Associated
Ideas

Did not discover what you have been on the lookout for? Or wish to know extra data
Math Solely Math.
Use this Google Search to search out what you want.

RELATED ARTICLES