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The method of addition of items of size is strictly much like addition of unusual numbers.
Learn the way the values of size are organized
in numerous columns for the addition of size.
1. Add 15 m 18 cm and 16 m 22 cm
Resolution:
Case 1:
Lengths to be added are transformed into cm.
15 m 18 cm = 1500 cm + 18 cm = 1518 cm
16 m 22 cm = 1600 cm + 22 cm = 1622 cm
Now, sum
1 1
1518 cm
+ 1622 cm
3140 cm
= 31 m 40 cm
Due to this fact, 15 m 18 cm + 16 m 22 cm = 31 m 40 cm
Case 2:
m cm
1 1
15 18
+ 16 22
31 40
(i) First cm are added, 18 cm + 22 cm= 40 cm. This sum is positioned beneath cm column
(ii) Now meters are added, 15 m + 16 m = 31 m. This 31 m is positioned beneath m column.
Therefore, sum = 31 m 40 cm.
2. Add 16 m 17 cm and 20 m 23 cm
Resolution:
Case 1:
Lengths to be added are transformed into cm.
16 m 17 cm = 1600 cm + 17 cm = 1617 cm
20 m 23 cm = 2000 cm + 23 cm = 2023 cm
Now, sum
1
1617 cm
+ 2023 cm
3640 cm
= 36 m 40 cm
Due to this fact, 16 m 17 cm + 20 m 23 cm = 36 m 40 cm
Case 2:
m cm
1
16 17
+ 20 23
36 40
(i) First cm are added, 17 cm + 23 cm= 40 cm. This sum is positioned beneath cm column
(ii) Now meters are added, 16 m + 20 m = 36 m. This 36 m is positioned beneath m column.
Therefore, sum = 36 m 40 cm.
3. Add 62 m 34 cm, 27 m 73 cm and 9 m 5 cm.
Resolution:
|
Allow us to add Step I: Prepare the numbers vertically. Step II: Write the lengths to be added in m and cm as proven. Step III: First, add centimetres from proper after which add the metres. |
 |
Thus, 62 m 34 cm + 27 m 73 cm + 9 m 5 cm = 99 m 12 cm
4. Add 45 m 37 cm and 31 m 92 cm.
Resolution:
Case 1:
45 m 37 cm = (45 × 100) cm + 37 cm = (4500
+ 37) cm = 4537 cm
31 m 92 cm = (31 × 100) cm + 92 cm = (3100
+ 92) cm = 3192 cm
Now, sum
1
4537 cm
+ 3192 cm
7729 cm
= 77 m 29 cm
Due to this fact, 45 m 37 cm + 31 m 92 cm = 77 m
29 cm
Case 2:
m cm
1
45 37
+ 31 92
77 29
(i) 37 cm + 92 cm = 129 cm = 1 m 29 cm. 29
is positioned beneath cm column and 1 m is carried over to m column.
(ii) Now 1 m + 45 m + 31 m = 77 m. It’s
positioned beneath m column.
Therefore,
sum = 77 m 29 cm.
5. Add 38 m 26
cm, 7 m 5 cm and 45 m 73 cm.
Resolution:
The values of size
are organized in columns of m and cm after which added.
m cm
2 1 1
38 26
7 05
+ 45 73
91 04
(i) 26 cm + 05 cm + 73 cm = 104 cm = 1 m 04 cm.
04 is positioned beneath cm column and 1 m is carried over.
(ii) 1 m + 38 m + 7 m + 45 m = 91 m and it’s positioned beneath m
column.
Therefore, the sum = 91 m
04 cm
6. Add 4 km 476 m
and 5 km 54 m.
Resolution:
Case 1:
Kilometers are turned into meters
4 km 476 m = (4 × 1000) m + 476 m = 4000 m + 476 m = 4476 m
5 km 54 m = (5 × 1000) m + 54 m = 5000 m + 54 m = 5054 m
Now sum 1 1
4476 m
+ 5054 m
9530 m
= 9 km 530 m
Due to this fact, 4 km 476 m +
5 km 54 m = 9 km 530 m
Case
2:
km m
1 1
4 476
+ 5 054
9 530
(i) 476 m + 054 m = 530 m, which
goes beneath m.
(ii) 4 km + 5 km = 9 km, which
goes beneath km.
Therefore, the sum = 9 km
530 m
7. Add 37 km 963
m, 28 km 54 m and eight km 181 m.
Resolution:
Kilometer and meter are organized in numerous columns and
then added.
km m
2 1 1
37 963
28 054
+ 8 181
74 198
(i) 963 m + 54 m + 181 m = 1198 m = 1 km 198 m.
198 m is positioned beneath column of meters and 1 km is carried
over.
(ii) 1 km + 37 km + 28 km + 8 km = 74 km
It’s positioned beneath km column.
Therefore, the sum = 74
km 198 m
8. Add the
following:
m dm cm
26
7 8
+ 52 5 6
Resolution:
m dm cm
1 1
26 7 8
+ 52 5 6
79 3 4
(i) 8 cm + 6 cm = 14 cm = 1 dm 4 cm
4 cm is positioned beneath cm column and 1 dm is carried over.
(ii) 7 dm + 5 dm + 1 dm = 13 dm = 1 m 3 dm
3 dm is positioned beneath dm column and 1 m is carried over.
(iii) 1 m + 26 m + 52 m = 79 m
Therefore, the sum = 79 m
3 dm 4cm
So as to add lengths, write the numbers of km, m and cm in separate columns then add like unusual numbers ranging from the best.
9. Add 46 km 143 m and 53 km 200 m.
km m
46 143
+ 53 200
_ 99 343
Due to this fact, 46 km 143 m and 53 km 200 m = 99 km 343 m
10. Add 28 km 76 m, 12 km 44 m & 21 km 38 m
km m
28 76
12 44
+ 21 38
_ 62 58
Questions and Solutions on Addition of Size:
1. Add the next.
(i) 32 m 78 cm + 15 m + 9 cm
(ii) 22 m 98 cm + 63 m + 89 cm + 7 m 7 cm
(iii) 143 m 50 cm + 112 m + 76 cm + 84 m 45 cm
(iv) 78 m 36 cm + 15 m 8 cm
(v) 153 m 28 cm + 49 m 25 cm + 70 m 20 cm
(vi) 69 m 59 cm + 15 m 15 cm + 56 m 9 cm
Solutions
1. (i) 47 m 87 cm
(ii) 93 m 94 cm
(iii) 340 m 71 cm
(iv) 93 m 44 cm
(v) 272 m 73 cm
(vi) 140 m 83 cm
2. Add the next.
(i) 139 m 68 cm, 66 m 46 cm and 42 m 7 cm
(ii) 140 m 23 cm, 33 m 48 cm and 32 m 17 cm
(iii) 179 m 16 cm, 69 m 59 cm and seven m 6 cm
(iv) 35 m 50 cm, 317 m 46 cm and 93 m 47 cm
(v) 64 m 18 cm, 48 m 36 cm and 14 m 82 cm
Solutions
2. (i) 248 m 21 cm
(ii) 205 m 88 cm
(iii) 255 m 81 cm
(iv) 446 m 43 cm
(v) 127 m 36 cm
3. Add the next:
|
(i) |
m cm 18 00 + 23 00 ____________ |
(ii) |
m cm 31 50 + 46 00 ____________ |
|
(iii) |
m cm 34 02 + 43 06 ____________ |
(iv) |
m cm 68 25 + 36 70 ____________ |
|
(v) |
m cm 43 62 + 27 34 ____________ |
(vi) |
m cm 93 75 + 29 25 ____________ |
|
(vii) |
m cm 74 50 + 58 70 ____________ |
(viii) |
m cm 47 84 + 6 58 ____________ |
● Associated
Ideas
● Conversion
of Commonplace Unit of Size
From Addition of Size to HOME PAGE
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