Home Math Divide by Repeated Subtraction | Subtracted Repeatedly |Solved Instance

### Divide by Repeated Subtraction | Subtracted Repeatedly |Solved Instance

Methods to divide by repeated subtraction?

We’ll learn to discover the quotient and the rest by the strategy of repeated subtraction a division drawback could also be solved.

DIVISION AS REPEATED SUBTRACTION

As multiplication is repeated addition, division is repeated subtraction.

Allow us to see how.

We all know that division is equal distribution of objects.

Once we divide, we learn how many occasions we are able to subtract the given quantity from the group of objects.

Allow us to perceive this with the assistance of following examples.

1. 12 pens need to be equally stored in 2 penstands.

So, what number of occasions can 2 be taken away from 12?

Allow us to subtract 2 time and again from 12 until we attain 0.

 12 – 2 = 10
 10 – 2 = 8
 8 – 2 = 6
 6 – 2 = 4
 4 – 2 = 2
 2 – 2 = 0

What number of occasions 2 has been subtracted from 12 to succeed in 0? Clearly, 6

Due to this fact, 12 ÷ 2=6

Solved examples on divide by repeated
subtraction:

1. Resolve 16 ÷ 8

Resolution:

8 is subtracted
repeatedly from 16 as proven:

When 8 is subtracted from 16, 2 occasions, then we get the rest zero.

Therefore, 16 ÷ 8 = 2, 2 is the quotient.

2. Divide 20 ÷ 5

5 is subtracted
repeatedly from 20 as proven:

When 5 is
subtracted from 20, 4 occasions, then we get the rest zero.

Therefore, 20
÷ 5 = 4, 4 is the quotient.

3. Resolve 12 by 3

Resolution:

3 is subtracted
repeatedly from 12 as proven:

When 3 is
subtracted from 12, 4 occasions, then we get the rest zero.

Therefore, 12
÷ 3 = 4, 4 is the quotient.

4. Divide 28 ÷ 7

7 is subtracted
repeatedly from 28 as proven:

When 7 is
subtracted from 28, 4 occasions, then we get the rest zero.

Therefore, 28 ÷ 7 = 4,
4 is the quotient.

5. Divide 32 ÷ 4

4 is subtracted
repeatedly from 32 as proven:

When 4 is
subtracted from 32, eight occasions, then we get the rest zero.

Therefore, 32
÷ 4 = 8, 8 is the quotient.

6. Resolve 18 by 6.

6 is subtracted
repeatedly from 18 as proven:

When 6 is
subtracted from 18, 3 times, then we get the rest zero.

Therefore, 18
÷ 6 = 3, 3 is the quotient.

7. Divide 12 flowers in 3 vases.

We put 1 flower in every of the three vases and subtract 3 from 12 every time.

12 – 3 = 9

9 – 3 = 6

6 – 3 = 3

3 – 3 = 0

There are not any extra flowers left. We subtracted 4 occasions 3 from 12.

We subtract 3 flowers 4 occasions from 12 to get 0.

7. Divide 18 ice lotions amongst 6 kids by repeated subtraction.

8. Discover 12 ÷ 4 by repeated subtraction.

Instance:

12 – 4 = 8        8 – 4 = 4       4 – 4 = 0

4 could be subtracted 3 occasions from 12. So, 12 ÷ 4 = 3

The above examples will assist us to unravel varied division issues on 2-digit quantity by a single digit quantity utilizing the strategy of repeated subtraction.

Division by Equal Distribution:

When 8 balls are equally distributed in 2 boys, we write 8 ÷ 2 = 4

Questions and Solutions on Divide by Repeated Subtraction:

1. Divide utilizing repeated subtraction. One has been achieved for you.

(i) Divide 16 by 4.

 T     O      1     6      –     4      1    2 T     O      1     2      –     4            8 T     O             8      –     4            4 T     O             4      –     4            0 16 ÷ 4 = 4

(ii) Divide 6 by 2.

 T     O             6      –     2 T     O T     O T     O 6 ÷ 2 = __

(iii) Divide 12 by 3.

 T     O      1     2      –     3 T     O T     O T     O 12 ÷ 3 = __

(iv) Divide 20 by 5.

 T     O      2     0      –     5 T     O T     O T     O 20 ÷ 5 = __

(v) Divide 14 by 7.

 T     O      1     4      –     7 T     O T     O T     O 14 ÷ 7 = __

1. (ii)

 T     O             6      –      2             4 T     O             4      –      2             2 T     O             2      –      2             0 6 ÷ 2 = 3

(ii)

 T     O      1     2      –     3            9 T     O             9      –      3             6 T     O             6      –      3             3 T     O             3      –      3             0 12 ÷ 3 = 4

(iii)

 T     O      2     0      –     5     1     5 T     O      1     5      –     5     1     0 T     O      1     0      –     5            5 T     O             5      –      5             0 20 ÷ 5 = 4

(iv)

 T     O      1     4      –     7            7 T     O             7      –      7             0 14 ÷ 7 = 2

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