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### Including Numbers in Expanded Kind

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Study to rearrange for including numbers
in expanded type (briefly type and in lengthy type). The numbers are written in
column type; the digits are organized in expanded type after which lastly discover the
sum of the given numbers.

Solved examples on including numbers in expanded
type:

1. Add 32 and 25

Answer:

Numbers are written in column
type        T      O

3       2

+   2       5

5       7

Including ones:  2 ones + 5 ones = 7 ones

This 7 is written in a single’s
column.

Including tens: 3 tens + 2 tens = 5
tens

This 5 is written in tens
column.

Thus, reply is 57

2. In different approach, add the expanded type of the numbers 32 + 25

Answer:

32     =  30 + 2       Expanded type of the numbers

+
25     =  20 + 5

=  50 + 7

=  57

The numbers are written in expanded
type as 32 = 30 + 2 and 25 = 20 + 5.

Now digits of 1’s place are
added, i.e., 2 + 5 = 7.

Once more numbers of ten’s place are
added, i.e., 30 + 20 = 50

Subsequently, complete sum = 50 + 7 =
57

3. Add 63 and 35 in lengthy type.

Answer:

Numbers are positioned in column

63      Sum of digit of 1’s place = 3 ones +
5 ones = 8 ones

35
Sum of digit of
ten’s place = 6 ten’s + 3 ten’s = 9 ten’s

Subsequently, sum =        98      =
9 ten’s + 8 ones

4. Add 38 and 61 briefly type.

Answer:

38         Sum of digit of 1’s
place = 8 + 1 = 9

+   61        Sum
of digit of ten’s place = 30 + 60 = 90

Subsequently,
sum =      99                                              = 90 + 9

5. Add 23, 31 and 44

Answer:

23        Sum of digit of 1’s place =
3 + 1 + 4 = 8

+  31       Sum
of digit of ten’s place = 2 + 3 + 4 = 9

+  44

Subsequently, sum =        98

Extra solved examples on 3-digits for including numbers in expanded type.

6. Add 314 and 563

Answer:

First the digits are organized in
columns

Sum of digit of 1’s place = 4
+ 3 = 7

Sum of digit of ten’s place = 1 +
6 = 7

Sum of digit of hundred’s place
= 3 + 5 = 8

314

563

Subsequently, sum =     877

7. Add 361 and 527 by arranging the numbers in expanded type.

Answer:

 361 = 3 lots of + 6 tens + 1 one +  527 = 5 lots of + 2 tens + 7 one  Sum   = 8 lots of + 8 tens + 8 one           =888 or,        361 = 300 + 60 + 1         +  527 = 500 + 20 + 7        Sum     = 800 + 80 + 8                   = 888

8. Add 231, 402 and 355

Answer:

231        ones         = 1 + 2 + 5 = 8

+  402        tens         = 3 + 0 + 5 = 8

+  355        lots of  = 2 + 4 + 3 = 9

Subsequently, addition sum = 988

2nd Grade Math Apply

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